The center of a circle is located at c(3,- 13). the x-axis is tangent to the circle at (3,9). find the equation of the circle. a x +y = 169 b. (x – 3)? +(y+13)? = 169 c (-3)2 + y2 = 169 d. (x – 3)2 + (y-13)2 = 169

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# The center of a circle is located at c(3,- 13). the x-axis is tangent to the circle at (3,9). find

The center of a circle is located at c(3,- 13). the x-axis is tangent to the circle at (3,9). find the equation of the circle. a x +y = 169 b. (x – 3)? +(y+13)? = 169 c (-3)2 + y2 = 169 d. (x – 3)2 + (y-13)2 = 169